Question

If x – y = 4 and x2+ y2= 20, find xy.

Answer 1

Answer:

here is tha answer y = 2 and x = 2

Answer 2

Answer:

$x - y = 4 - (i)\\ {x}^{2} + {y}^{2} = 20 - (ii) \\\blue{\mathfrak{ \bf\underline{{subtract \: - 2xy \:on \: both \: in \: {eq}^{n} \: (ii) }}}:} \\ {x}^{2} + {y}^{2} - 2xy = 20 - 2xy \\ {(x - y)}^{2} = 20 - 2xy \\\blue{\mathfrak{ \bf\underline{{From \: {eq}^{n} (i) }}}:}\\ {(4)}^{2} = 20 - 2xy \\ 16 = 20 - 2xy \\ 2xy = 20 - 16 \\ 2xy = 4 \\ \boxed{xy = 2} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$