Math, asked by ToxicEgo, 11 months ago

if x+ y= 4 and x²+y²=7, then find the value of xy​

Answers

Answered by warylucknow
3

The value of xy is 4.5.

Step-by-step explanation:

The expansion of (a + b)² is:

(a + b)² = a² + 2ab + b²

It is provided that:

(x + y) = 4

(x² + y²) = 7

Compute the value of xy as follows:

(x + y)² = x² + 2xy + y²

(x + y)² = x² + y² + 2xy

(4)² = 7 + 2xy

16 - 7 = 2xy

9 = 2xy

xy = 4.5

Thus, the value of xy is 4.5.

Learn more:

https://brainly.in/question/12906774

Answered by Utkarshkesharwani933
2

Answer:

x + y = 4

x² + y² = ( x + y )² - 2xy

7 = (4)² - 2xy

7 = 16 - 2xy

2xy = 16 - 7

xy = 9

xy = 9/2

Follow me

Mark as brainlist

Similar questions