If x-y =4 and x2+y2=80 find xy
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2
check the attachment
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Answered by
0
Answer:
32
Step-by-step explanation:
x-y=4
x^2+y^2=80
(x-y)^2=x^2+y^2-2xy
4^2=80-2xy
16=80-2xy
2xy=80-16
2xy=64
xy=32
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