if x-y=4 and xy=1,find the value of x3-y3
Answers
Answered by
0
Step-by-step explanation:
( x - y)^3 = x^3 - y^3 - 3xy (x - y)
Putting the value,
(4)^3 = x^3 - y^3 - 3(1) (4)
64 = x^3 -y^3 - 12
x^3 - y^3 = 64+ 12= 76
Answer. x^3 - y^3 = 76
Similar questions