Math, asked by pk7092501, 29 days ago

if x-y=4 and xy=1,find the value of x3-y3​

Answers

Answered by madhuwailic
0

Step-by-step explanation:

( x - y)^3 = x^3 - y^3 - 3xy (x - y)

Putting the value,

(4)^3 = x^3 - y^3 - 3(1) (4)

64 = x^3 -y^3 - 12

x^3 - y^3 = 64+ 12= 76

Answer. x^3 - y^3 = 76

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