If x+y=4 and xy=-12 find the value of x-y
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3
Answer:
(x+y)²=x²+y²+2xy.
=>4²=x²+y²+2(-12)
=>x²+y²=16+24=40
(x-y)²=x²+y²-2xy
=40-2(-12)
=64
=>x-y=8
Answered by
0
Answer:
-₹7₹6₹&₹&
Step-by-step explanation:
-₹-₹-₹;#+7#6₹&&₹&₹&₹&₹₹&-#82363537282
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