If x - y = 4 and xy = 12, then find the value of x3-y3
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Answered by
17
Answer:
x-y =4, xy =12
find value of x ³- y³
x³ - y ³= ( x- y ) ( x ² + y ² + xy )
=(4)(x² + y ²+12)...... 1
as find value of x² + y²
(x-y)²= x² +y² -2xy
(4)² =x² + y² - 2(12)
16 =x² + y² -24
16+24 =x²+y²
40 =x² + y²
put value in ....1
x³-y³= (4)(40+12)
=(4)(52)
= 208
x³-y³ = 208
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Answered by
1
Answer:
208 is the answer
Step-by-step explanation:
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