if X + Y =4 and XY= 2 , find the value of x ^2 + y^2 also analyse which identity will be used.
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Answered by
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x^2 + y^2
= (x+y)^2 - 2xy
= (4)^2 - 2 × 2 [ x+y=4 ; xy=2]
= 16 - 4
= 12
Answered by
0
Step-by-step explanation:
given: X + Y = 2
XV=2
To find : X² + Y²
SOL.
X² + Y² = (X+Y)² - 2XY
X² + Y² = (4)² - 2(2)
X² + Y² = 16 - 4
X² + Y² = 12
Identity used : (a+b)² = a² + b² + 2ab
a² + b² = (a+b)² - 2ab
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