Question

If x+y=4 and xy=2, find the value of x²+y²​

Answer 1

Refer my attached documents for your answer

Answer 2

$\bf \LARGE \color{pink}Hola!$

GiveN :

$\sf \mapsto \: (x + y) = 4$

$\sf \mapsto \: xy = 2$

To FinD :

$\sf \mapsto \: {x}^{2} + {y}^{2} = {?}$

SolutioN :

$\: \: \: \: \: \: \: \: \: \: \sf \: {(x + y)}^{2} = 4^{2}$

$\implies \sf \: {x}^{2} + {y}^{2} + 2xy = 16$

$\sf \implies \: {x}^{2} + {y}^{2} - 2 \times 2 = 16 \: \: \: \: \: \bf[ \: Given \: \: ;\: \: xy = 2 \: ]$

$\: \: \: \: \: \: \: \: \sf \therefore{ \underline{ \boxed {\sf{ {x}^{2} + {y}^{2} = 12 }}}}$

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HOPE THIS IS HELPFUL...