If x+y= -4 and xy= 2, then find the value of x^2+y^2
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Answer:
(x+y)^2 = x^2+ y^2 + 2xy
(-4)^2 = x^2+ y^2 +2(2)
16 = x^2+y^2+4
16-4 = x^2+ y^2
x^2 + y^2 = 12
Therefore the answer is 12
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