Question

if x+y=-4 and xy=2 then find x^2+y^2​

Answer 1

Answer:

Step-by-step explanation:

(x + y) = 4

Squaring both sides

(x + y)^2 = 4^2

x^2 + y^2 + 2xy =16

Substituting value of xy = 2 in the above equation we get

x^2 + y^2 + 2 × 2 = 16

x^2 + t^2 + 4 = 16

x^2 + y^2 = 16 - 4

x^2 + y^2 = 12

Pl mark as brainliest

Answer 2

Answer:

use (x+y)^2=(-4)^2

Step-by-step explanation:

(x+y)^2   =    (-4)^2

x^2+y^2+2xy = 16

SUBSTITUTING VALUES

x^2+y^2+2(2) = 16

x^2+y^2 = 16-4

x^2+y^2 = 12