Question

If(x-y)=4 and xy =21,find the value of x³-y³

Answer 1

according to the formula :-

Given that : x-y =4

xy= 21

x^3 -y^3 = (x-y)^3 + 3xy (x-y)

= (4)^3 +3 (21) (4)

= 64 + 252

= 316.

Hope it helps you......

Thanks

Answer 2

Answer:

the answer is  316...

Step-by-step explanation: