Question

If(x-y)=4 and xy =21,find the value of x³-y³​

Answer 1

Answer:

given that x-y =4 and xy= 21

Step-by-step explanation:

x^3-y^3= (x-y)^3+3xy(x-y)

(4)^3+3(21)(4)

64+252=316

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