If x+y=4 and xy=3, find the value of x^2+Y^2.
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I guess the answer is 10
If we take x as 3 and y as 1
x+y = 3+1 = 4
xy = x multiplied by y = 3 x 1 = 3
So...x^2 + y^2 = 3^2 + 1^2 = 3x3 + 1x1 = 9 + 1 = 10
Hope this helps
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If we take x as 3 and y as 1
x+y = 3+1 = 4
xy = x multiplied by y = 3 x 1 = 3
So...x^2 + y^2 = 3^2 + 1^2 = 3x3 + 1x1 = 9 + 1 = 10
Hope this helps
Please mark as brainliest
shizashaheem:
Please mark as brainliest
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