if x-y=4 and xy=45. Find x3-y3
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Answered by
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x=4-x,y=4-x
(4+y)3-(4-x)3=0
12+3y-12-3x=0
3y-3x=0
3(y-x)=0
y-x=0
(4+y)3-(4-x)3=0
12+3y-12-3x=0
3y-3x=0
3(y-x)=0
y-x=0
Answered by
0
Answer:
604
Step-by-step explanation:
X-Y = 4
Squraing both sides
X^2 + Y^2 - 2XY = 16
XY = 45
X^2 + Y^2 - 90 = 16
X^2 +Y^2 = 106
(X+Y)^2 = X^2 + Y^2 + 2XY
(X+Y)^2 = 106 + 90
(X+Y)^2 = 196
X+Y = +/-14
X-Y = 4
X= 9 , -5
Y= 5, -9
X^3 - Y^3
= 9^3 -5^3 = 729-125=604
= (-5)^3 - (-9)^3 = -125 + 729 = 604
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