If x+y=4 nd xy=2 then find x^2+y^2
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(x+y)^2=x^2+y^2+2xy...4^2=x^2+y^2+2*2.....x^2+y^2=16-4.....x^2+y^2=12
tanvi759:
Oho!!!! Its x^2+y^2 nt (x+y)^2
What??
What do I have to find???
Your question states x^2+y^2
Answered by
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(x+y)² = x² + y² + 2xy
(4)² = x² + y² + 2(2)
16 = x² + y² + 4
x² + y² = 16 - 4 = 12
(4)² = x² + y² + 2(2)
16 = x² + y² + 4
x² + y² = 16 - 4 = 12
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