Question

if x+y=4, then find the value of x^3+y^3+12xy-64

please answer someone

Answer 1

[x+y]^3=x^3+y^3+3xy[x+y]

64=x^3+y^3+3xy[4]

64=x^3+y^3+12xy

x^3+y^3+12xy-64=0