IF X+Y=4, THEN FIND THE VALUE OF X CUBE +Y CUBE + 12XY - 64
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Step-by-step explanation:
(x+y) = 4
Taje a cube of both sides
=> (x+y)^3 = 4^3
= x^3 + y^3 +3xy(x+y) = 64
= Substitute the value of x+y=4 in the above eq.
x^3 +y^3 + 3xy(4) = 64
=x^3 + y^3 + 12xy =64
Or
x^3 + y^3 + 22xy -64 =0
which is the required ans.
Hope it is clear
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