Question

if x+y = 4 then find x³+y³-12xy+64​

Answer 1

Answer:

(x+y)^3-12xy+64

4^3-12xy+64=0

48-12xy+64=0

16-12xy=0

-12xy=-16

xy=-16/12

xy=-8/6

y=-8/6x

x+y=4

x+-8/6x=4

x=4×6x/8

x=24x/8

x=3x