Question

If x+y=4,then value of x^3+y^3+12×x×y-64

Answer 1

Answer

x +y =4

cube on both sides

You will get

( x +y )³ = 4³

x³ + y³ + 3xy . ( x + y ) = 64

x³ +y³ + 3xy . 4 = 64

x³ + y³ +12xy = 64

x³ +y³ +12xy -64 = 0

Answer 2

Answer :-

0

Explanation :-

Here is your answer.

Given that, x+y = -4

The formula, x³ + y³ -12xy +64

=> (x + y )³ - 3xy ×4 - 12xy+64

=> (x + y )³ - 3xy ( x+y) - 12xy + 64

=> (-4)³ - 3xy (-4) - 12xy + 64

=> -64 + 12xy - 12xy + 64

=> 0

hope it helps ✌️ ✌️

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