if x - y = 4, xy = 12 , then find x² + y²
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40 is the ryt answer
given, x-y=4 -eq.1
xy=12 -eq.2
so, x=4+y -eq3
put the value of x in the form of y in eq.2
so we get, (4+y)y=12
4y+y²=12
y²+4y-12=0
y²+(6-2)y-12=0 (by factors of 12 )
y²+6y-2y-12=0
y(y+6)-2(y+6)=0
(y+6)(y-2)=0
y=-6,2
put the value of y in eq3
we get x=-2,6
now we have to find x²+y²
we have values of x and y so we easily find x²+y²
which is (-2)²+(-6)² or 6²+2² =40 answer
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