Question

If x + y = 40, y + z = 58 and z + x = 52 then find the value of z.

Answer 1

x+y=40
y=40-x
40-x+z=58
z-x=18 .............a

z=52-x
replacing values in equation a,
52-2x=18
52-18=2x
34=2x
x=34/2=17

replace values
z+x=52
z=52-17=35

Answer 2

Answer:

35

Explanation:Add this three equation:

    x+y=40

    y+z=58

    z+x=52

2(x+y+z)=40+58+52=150

x+y+z=75

(x+y)+z=75

40+z=75

z=35