Question

If x + y = 40, y + z = 58 and z + x = 52, then find the
value of (z – y).
(A) 10 (B) 12
(C) 14 (D) 15

pls give detailed explanation in an easy way and i will mark as brainliest

Answer 1

Answer:

x+y=40 (1)

y+z=58 (2)

z+x=52 (3)

Now, in (1)

x+y= 40

x=40-y

Substituting the value of x in (3)

z+x= 52

z+ (40-y) =52

z+40-52= y (Bringing numbers together)

z-12= y

Substituting the value of y in (2)

y+z= 58

(-12+z) + z=58

-12+z+z=58

-12+2z= 58

2z= 58+12

2z= 70

z=35

Substituting the value of z in (2)

y+z=58

y+35= 58

y=23

(z-y)

35-23 = 12

Therefore, option B is the right answer.