Question

If x+y=42, y+z=68, and x+z=88, then x=?

Answer 1

it is your answer and thanks for your question

Answer 2

The answer goes like this :

x+y = 42 ....(I)
y+z = 68 ....(II)
x+z = 88 ....(III)

Adding the three equations..
=> x+y+y+z+x+z = 42+68+88
=> 2x+2y+2z = 198
=> 2(x+y+z) = 198
=> x+y+z = 99
=> x = 99-y-z .....(IV)

Substituting the value of x in equation (I)
=> x+y = 42
=> 99-y-z+y = 42
=> 99-z = 42
=> -z = 42-99
=> -z = -57
=> z = 57

Substituting the value of z in equation (II)
=> y+z = 68
=> y+57 = 68
=> y = 68-57
=> y = 11

Substituting the value of y in (I)
=> x+y = 42
=> x+11 = 42
=> x = 42 - 11
=> x = 31

Hence, x = 31, y = 11, z = 57

Checking...
x+y = 42 i.e. 31+11=42.
y+z = 68 i.e. 11+57=68.
x+z = 88 i.e. 31+57=88.

Hence all the conditions satisfy, therefore the answer is correct ..✌

Hope and anticipate It'll help you a lot...

If you get it correctly, then Mark it as Brainliest !