Question

if X+y=4and XY=2 find the value of x^2+y^2​

Answer 1

Answer:

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Answer 2

Answer:

x^2+y^2=12

Step-by-step explanation:

x^2+y^2=[x+y]^2

x^2+y^2+2xy=[x+y]^2

x^2+y^2+2*2=16

x^2+y^2+4=16

x^2+y^2=16-4

x^2+y^2=12