If x-y=4and xy=21 find the value of x3-y3 by using formula a3-b3 -3ab a-b
Answers
Answered by
1
Answer:
316
Explanation:
Given that : x-y =4
xy= 21
x^3 -y^3 = (x-y)^3 + 3xy (x-y)
= (4)^3 +3 (21) (4)
= 64 + 252
= 316.
Answered by
1
Answer:
316
Explanation:
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