Accountancy, asked by MASTERkid007AYUSH, 5 hours ago

If x-y=4and xy=21 find the value of x3-y3 by using formula a3-b3 -3ab a-b

Answers

Answered by bhuyanayush2008
1

Answer:

316

Explanation:

Given that : x-y =4

xy= 21

x^3 -y^3 = (x-y)^3 + 3xy (x-y)

= (4)^3 +3 (21) (4)

= 64 + 252

= 316.

Answered by bhadwonkabaap6969696
1

Answer:

316

Explanation:

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