If x+y+4z=6,3x+2y-2z=9,5x+y+2z=13 then write the augumented matrix form
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Given equations are x+y+4z=6,3x+2y−2z=9,5x+y+2z=13
Therefore, D=∣∣∣∣∣∣∣∣1351214−22∣∣∣∣∣∣∣∣=1(4+2)−1(6+10)+4(3−10)
=6−16−28=−38
D1=∣∣∣∣∣∣∣∣69131214−22∣∣∣∣∣∣∣∣=6(4+2)−1(18+26)+4(9−26)
=6(6)−44+4(−17)=36−44−68=−76
D2
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