Question

..If x + y + 5 = 0, then what is the value of (x + y)^2
pls tell me the correct answer..
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Answer 1

Answer:

x+y+2 = 0                                 x3+y3+8

Taking cube not on both sides 

(x+y+2)3=0

x3+y3+8(x+y+2)(xy+2y+2x)=0.

x3+y3+8+(0)(xy+2y+2x)=0

x3+y3+8=0

Step-by-step explanation:

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Answer 2

Answer

x + y = 5

Put x = 3 in equation (i), we get

3+y=5

∴y=5−3

∴y=2