If x+y=5 and 4 xy=21 find x3+y3
Answers
Answered by
0
Answer:
x³+y³
=(x+y)³-3xy(x+y)
=(5)³-3×4×5
=125-60
=65
Answered by
0
Answer:
The identity is xˆ3 + yˆ3 = (x+y)ˆ3 - 3xy(x+y)
Now substituting x+y = 5 and xy =21/4 in the identity
xˆ3 + yˆ3 = 5ˆ3 -3*21/4(5)
= 125 - 78.75
46.25
Step-by-step explanation:
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