Question

if x+y=5 and 4xy=21,find x3+y3​

Answer 1

Answer:

185/4

Step-by-step explanation:

x+y=5

4xy=21 –> xy=21/4

x³+y³

=(x+y)(x²+y²-xy)

=(x+y)([(x+y)²-2xy]-xy)

=(x+y)[(x+y)²-3xy]

=5*[5²-3(21/4)]

=5[25-63/4]

=185/4

Answer 2

Answer:

hope this is correct

Step-by-step explanation:

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