If x+y = 5 and x^2 + y^2 = 111, then the value of x^3 + y^3
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Here is your answer :-
____________(^-^)______________
x + y = 5
( x + y )^2 = 25
=> x^2 + y^2 + 2xy = 25
=> 11 + 2xy = 25
=> 2xy = 25 - 11
=> xy = 14/2
=> xy = 7
( x + y )^3 = x^3 + y^3 + 3xy ( x + y )
( 5 )^3 = x^3 + y^2 + 3 × 7 × 5
125 = x^3 + y^3 + 105
x^3 + y^3 = 20
Here is your answer :-
____________(^-^)______________
x + y = 5
( x + y )^2 = 25
=> x^2 + y^2 + 2xy = 25
=> 11 + 2xy = 25
=> 2xy = 25 - 11
=> xy = 14/2
=> xy = 7
( x + y )^3 = x^3 + y^3 + 3xy ( x + y )
( 5 )^3 = x^3 + y^2 + 3 × 7 × 5
125 = x^3 + y^3 + 105
x^3 + y^3 = 20
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