If x -y = 5 and xy= 14 find the value of x square- y square??????
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x - y = 5
x y = 14 and y = 14 /x
x = 5 + y
x = 5 + 14 /x
x^2 = 5x + 14
x^2 - 5x - 14 = 0
x^2 - 7x + 2x - 14 = 0
x ( x - 7 ) + 2( x - 7 ) = 0,
( x - 7 ) ( x + 2) = 0
x = 7, - 2
x = 7
Putting value of x,
x = 5 + y
7 - 5 = y
y = 2
x^2 - y^2 = ( 7) ^2 - ( 2 ) ^2
=> 49 - 4
=> 45
ANSWER : 45
x y = 14 and y = 14 /x
x = 5 + y
x = 5 + 14 /x
x^2 = 5x + 14
x^2 - 5x - 14 = 0
x^2 - 7x + 2x - 14 = 0
x ( x - 7 ) + 2( x - 7 ) = 0,
( x - 7 ) ( x + 2) = 0
x = 7, - 2
x = 7
Putting value of x,
x = 5 + y
7 - 5 = y
y = 2
x^2 - y^2 = ( 7) ^2 - ( 2 ) ^2
=> 49 - 4
=> 45
ANSWER : 45
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