Question

if x +y= 5 and xy=3 , find the value of ( x²+y²).​

Answer 1

Answer:

Total amount of investment is Rs 36,414

Step-by-step explanation:

Given :

A NAV of a mutual fund = Rs 238

Entry load = 2 %

No. of units to be purchased = 150

To find :

Amount of investment

Solution :

★ Purchase cost per unit to investors = NAV as on date of purchase + Entry load

⇒ 238 + 2 % of 238

⇒ 238 + 2 / 100 × 238

⇒ 238 + (\dfrac{2}{100} \times 238)238+(

100

2

×238)

⇒ 242.76

★ Purchase cost per unit to investors = Rs 242.76

• No. of units to be purchased = 150

★ Total amount of investment = No. of units to be Purchase × Purchase price per unit

⇒ 150 × 242.76

⇒ 36,414

Total amount of investment = Rs 36,414

Therefore,

Total amount of investment is Rs 36,414

Step-by-step explanation:

Answer 2

To find : value of $x^{2} + y^{2}$

Given : $x + y =5$ and $xy = 3$

Solution :

• As per the given data we know that  $x + y =5$ and $xy = 3$ .
• To find the value of $x^{2} + y^{2}$ we apply identity $(a +b )^{2} = a^{2} + 2ab + b^{2}$
• Here, $a = x$ and $b =y$
• Substituting the values we get ,
• $(x + y )^{2} =x^{2} + 2xy + y^{2}$  

       $(5)^{2} = x^{2} + 2(3) +y^{2} \\25 =x^{2} + 6 + y^{2} \\x^{2}+ y^{2} =25-6 \\x^{2}+ y^{2} = 19$

Hence , value of $x^{2} + y^{2}$ is $19$ .