If x+y = 5 and xy = 6, can you find a quadratic equation having x and y as solutions?
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if u find difficulty u can ask in comment section
Step-by-step explanation:
y = 5 - x .....1
from 1
x(5 - x) = 6
5x - x^2 = 6
-x^2 + 5x = 6
if we take -1 common just to eliminat -ve sing
x^2 - 5x + 6 =0
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