Question

If (x + y) = 5 and xy = 6, what is (x^3 + y^3)?

Answer 1

Step-by-step explanation:

x³+y³= (x+y)³-3xy(x+y)

= 5³-3×6×5

=125-90

= 35

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Answer 2

Answer:

35

Step-by-step explanation:

$\large \text{Given (x+y)=5 and xy=6}\\\\\\\large \text{squaring on both side (x+y)=5}\\\\\\\large \text{( x+y)^2=(5)^2 }\\\\\\\large x^2+y^2+2xy=25\\\\\\\large \text{Now substracting 3xy in both side we get }\\\\\\\large x^2+y^2-xy=25-3xy\\\\\\\large \text{putting value of xy = 6}\\\\\\\large x^2+y^2-xy=7\\\\\\\large \text{Now we have x^2+y^2-xy=7 and (x+y)=5}$

$\large \text{using identity a^3+b^3=(a+b)(a^2+b^2-ab) }\\\\\\\large x^3 + y^3=(5)(7)\\\\\\ \large x^3 + y^3=35\\\\\\\large \text{Thus we get answer 35 }$