if x-y=5 and xy=7, find the value of x^3-y^3.
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Step-by-step explanation:
Using Identities,
a³ - b³ = (a-b)(a² + b² + ab)
a² + b² - 2ab = (a-b)²
x³ - y³ = (x - y)(x² + y² + xy)
= 5 × ( x² + y² - 2xy + 3xy)
= 5 × ( (x-y)² + 3xy)
= 5 ×(5² + 3×7)
= 5× (25 + 21)
= 430
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