if x -y =5 and xy = 84 find x3 -y3
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X-Y=5
X=5+Y ---------->Equation I
XxY=84---------> II
Putting the value of X in equation II
(5+Y)xY=84
Y^2+5Y=84
Y^2+5Y-84=0
Y^2+12Y-7Y-84=0
Y(Y+12)-7(Y+12)=0 (quadratic form)
(Y+12)(Y-7)=0 (zero product rule)
Y=7
then X =12 (putting value of Y in any equation)
X^3-Y^3
=12^3-7^3
=1728-343
=1385
I was not sure if you had to find x cube - y cube
or
x into 3 - y into 3
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