if x+y=5
y+z=7
z+x=12
then what is the value of x, y, z
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Hey mate!
Here's your answer!
x+y = 5
=> x = 5-y ...(i)
y+z = 7
=> z = 7-y ...(ii)
z+x = 12 ...(iii)
Substituting (i) and (ii) in (iii),
7-y+5-y = 12
=> 12-2y = 12
=> y = 1/2
When y = 1/2,
x = 5-1/2
=> x = 9/2
Also,
z = 7-1/2
=> z = 13/2
Therefore, the values of x, y and z are 9/2, 1/2 and 13/2 respectively.
Hope it helps :)
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