If x:y=6:11 find (8x-3y):(3x+2y)
Answers
Answered by
102
let x=6k and y=11k
8x-3y=48k-33k=15k
3x+2y=18k+22k=40k
divide
=3:8
8x-3y=48k-33k=15k
3x+2y=18k+22k=40k
divide
=3:8
D060486365:
I can not understand it
since ratio is given so I took numbers as 6x 1and11x
Answered by
45
x=6k and y=11k
now,
8x-3y=(8*6k)-(3*11k)=48k-33k=15k
3x+2y=(3*6k)+(2*11k)=18k+22k=40k
now,
(8x-3y):(3x+2y)=15k:40k=15k/40k=3k/8k=3:8
now,
8x-3y=(8*6k)-(3*11k)=48k-33k=15k
3x+2y=(3*6k)+(2*11k)=18k+22k=40k
now,
(8x-3y):(3x+2y)=15k:40k=15k/40k=3k/8k=3:8
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