Question

if x+y=6 and x^3+y^3=12 find x y

Answer 1

Answer:

Step-by-step explanation:

Given that,

x + y = 6 and x³ + y³ = 12

x³ + y³ = ( x + y )³ - 3xy ( x + y ) (∵a³ + b³ (a + b)³ - 3ab ( a + b ) )

12 = ( 6 )³ - 3xy (6 )

12 = 216 - 18xy

18xy = 216 - 12

18xy = 204

xy = 204 / 18

xy = 34/3 is the answer.