Question

If x+y=6 and x-y=4,find 1)
${x}^{2} + {y}^{2}$
2)
$xy$

Answer 1

hi...
see the attachment :)

Answer 2

$x + y = 6.....1 \\ x - y = 4.....2$
adding 1 and 2
we get
$2x = 10 \\ x = 5$
put x=5 in 1
$x + y = 6 \\ 5 + y = 6 \\ y = 6 - 5 \\ y = 1$
${x}^{2} + {y}^{2} \\ {(5)}^{2} + {(1)}^{2} \\ 25 + 1 \\ 26$
$xy \\ 5 \times 1 \\ 5$
hope this helps you:-))))
don't forget to do it brainleist.