Question

if x+y=6 and x-y=4 find the value of a) x^2+y^2 and b) xy​

Answer 1

Answer:

X+y=6 (1)

x-y=4 (2)

After eliminating

We get 2x=10

X=5

Putting value of x in eq (1)

We get y=1

Then(i) x²+y²=(5)²+(1)²

=25+1=26

ii)xy=5*1=5

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Answer 2

According to your question, I have to find the value of a) x²+y² and b)=xy

and x+y=6 and x-y= 4 is given .

Let's find

x+y = 6

x + y = 6 -------(1)

x - y = 4 ------(2)

adding both x and y

y will be cancelled by another y

2x = 10

x = 10/2

x = 5

Now , putting the value of x in equ (1)

5 + y = 6

5 + y = 6

y = 6-5

y = 1

we get x = 5 and y = 1

to find x² + y²

x² + y² = (5)² + (1)²

= 25 + 1

= 26

and xy

xy = 5×1

= 5 .

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