if x+y=6 and x-y=4 find the value of a) x^2+y^2 and b) xy
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Answered by
2
Answer:
X+y=6 (1)
x-y=4 (2)
After eliminating
We get 2x=10
X=5
Putting value of x in eq (1)
We get y=1
Then(i) x²+y²=(5)²+(1)²
=25+1=26
ii)xy=5*1=5
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Answered by
1
According to your question, I have to find the value of a) x²+y² and b)=xy
and x+y=6 and x-y= 4 is given .
Let's find
x+y = 6
x + y = 6 -------(1)
x - y = 4 ------(2)
adding both x and y
y will be cancelled by another y
2x = 10
x = 10/2
x = 5
Now , putting the value of x in equ (1)
5 + y = 6
5 + y = 6
y = 6-5
y = 1
we get x = 5 and y = 1
to find x² + y²
x² + y² = (5)² + (1)²
= 25 + 1
= 26
and xy
xy = 5×1
= 5 .
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