Question

If (x+y) = 6 and x² - y²- 4^8 find (x-y) (x+y) = x² - y²

Answer 1

Answer:

x−y=8⇒x=y+8..(1)

Now, xy=2⇒y(y+8)=2⇒y

2

+8y−2=0..(2)

Now, Squaring (1)

x

2

=y

2

+16y+64⇒8y=

2

x

2

−y

2

−64

..(3)

From (2) and (3)

y

2

+

2

x

2

−y

2

−64

−2=0⇒

2

x

2

+y

2

−32−2=0⇒

2

x

2

+y

2

=34⇒x

2

+y

2

=68