Question

If (x+y) = 6 and x² - y²- 4^8 find (x-y) (x+y) = x² - y²
class 8
cbse

Answer 1

Answer:

hi friend, ez question , mark me brainliest for further help

Step-by-step explanation:

we know,

$(a-b)^2= a^2+b^2-2ab$

so we can write it as,

$(a-b)^2 + 2ab = a^2+b^2\\or\\(a-b)^2 - (a^2+b^2) = -2ab$                         (KEEP THESE FORMULAS IN MIND, THEY WILL HELP YOU TO SOLVE HIGHER QUESTIONS)

SO,

according to question,( which isnt very clear try writing question properly)

6^2= (x^2+y^2) + 4^8

36-(x^2+y^2) = 4^8

-(x^2+y^2) = (65536 - 36)

-(x^2+y^2) = 65500

x^2+y^2= -65500

FROM NOW ON, WRITE THE QUESTION PROPERLY