If (x-y)=6 and xy=1 , then find the value of x^3-y^3
Answers
Answered by
3
Step-by-step explanation:
x - y = 6
Doing cube both side
(x - y)³ = 216
x³ - y³ - 3xy(x-y) = 216
x³ - y³ - 3(1)(6) = 216
x³ - y³ = 216 + 18
= 234
Answered by
2
Answer:
(X-Y)^3=X^3-Y^3-3XY(X-Y)
=6^3=x^3-y^3-3*1*(6)
=216+18=x^3-y^3
Therefore x^3-y^3=234
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