Question

If x - y=6 and xy = 16, find the value of x + y.
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shall I do it now or afterwards..?​

Answer 1

Answer:

${(x + y)}^{2} = {(x - y)}^{2} + 2xy \\ {(x + y)}^{2} = {6}^{2} + 2 \times 16 \\ {(x + y)}^{2} = 36 + 32 \\ \: \: \: = 68 \\ x + y = \sqrt{68} \\ = 8.246 \\ thankyou$