Question

if(x+y)=6 and xy=2 , find the value of x cube+y cube​

Answer 1

Answer:

(x+y)^3 = 6 ^3

x^3 + y^3 + 3 (x+y) = 216

x^3 + y^3 + 3×6 = 216

x^3 + y^3 + 18 = 216

x^3 + y^3 = 216 - 18

x^3 + y^3 = 198

Answer 2

Answer:

$GIVEN\\x+y= 6\\xy=2\\\ identity-\\ (x+y)^{3} =x^{3} +y^{3} +3xy(x+y)\\ \\6^{3} =x^{3} +y^{3} +3 X 2X(6)\\\\216= x^{3} +y^{3} +36\\\\216-36 = x^{3} +y^{3} \\\\180 = x^{3} +y^{3}$