Question

If (x + y)=6 and xy=4, find the value of x²+y² and x³+y³.

Answer 1

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x+y=6

Squaring on both sides

x²+y²+2xy=36

x²+y²=28

x+y=6

Cubing on both sides

x³+y³+3xy(x+y)=216

x³+y³=216-72

x³+y³=144

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