If x+y = 6 and xy = 8, find x2 + y2
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Answered by
4
HERE IS YOUR ANSWER. .
take the equation x+y = 6
squaring both side
x^2 + y^2 +2xy = 36
x^2 + y^2 = 36 -2xy
x^2 + y^2 = 36 - 2 (8)
x^2 + y^2 = 36 - 16
x^2 + y^2 = 20
HOPE IT HELPS YOU! !!
take the equation x+y = 6
squaring both side
x^2 + y^2 +2xy = 36
x^2 + y^2 = 36 -2xy
x^2 + y^2 = 36 - 2 (8)
x^2 + y^2 = 36 - 16
x^2 + y^2 = 20
HOPE IT HELPS YOU! !!
Answered by
0
Answer:x+y=6
xy=8
y=8/x---------i
x+8/x=6
x2+8/x=6
x2-6x+8=0
x2-4x-2x+8=0
x=2,4
Step-by-step explanation:
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