if x+y=6, xy=8 find x2 +y2
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Given:
- x + y = 6......(I)
- xy = 8........(II)
To find:
- x² + y²
Process:
- Formula for (a+b)² :
- x² + 2xy + y²
- Let's put the values of variables and equate them to their formula:
- (x + y)² = (x + y)²
=> x² + 2xy + y² = (6)²
(Since x + y = 6 from(I))
=> x² + y² + 2(8) = 36
( xy = 8 from (II) and expanding (6)²)
=> x² + y² + 16 = 36
=> x² + y² = 36 - 16
=> x² + y² = 20
Answer:
Therefore x² + y² = 20
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