If x+y/7 =1/2 (log x + log y) then show x/y+y/x = 47
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Step-by-step explanation:
If log(x+y/7)=1/2(log x+log) then what is the proof of x/y+y/x=47?
log((x+y)/7)=1/2(logx+logy)
log((x+y)/7)=1/2(log(xy))
log((x+y)/7)=1/2(log(xy))
log((x+y)/7)=log(sqrt(xy))
(x+y)/7)=sqrt(xy)
Squaring on Both Sides,
(x+y)2=49xy
x2+y2+2xy=49xy
x2+y2=47xy
(x2+y2)/xy=47
x/y+y/x=47
Hence Proved!
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